5

I have recently started to get my feet wet by making some ginger beers using a ginger bug to start the fermentation. I would like to know the alcohol content of my final product, but as the ginger bug has both bacteria and yeast eating the sugars I can not figure out how I would measure the final alcohol content!

3 questions:

  1. Is there a way to figure out how much sugar has been consumed by either the yeast or bacteria, so I can then just use a hydrometer as suggested most places I search?
  2. Can I measure the alcohol content by some other indicator besides sugar content?
  3. What other tools might be used besides a refractometer or a hydrometer?
2
  • For dry wines, you can use a Vinometer, but I don't know if that will work for your ginger.
    – Robert
    Commented Feb 12, 2019 at 0:10
  • Thanks, but I would very rarely be fermenting out all the sugar as that would not taste nice, so if I understand this tool correctly then it will not work for me.
    – Jeppe
    Commented Feb 12, 2019 at 10:01

1 Answer 1

2

If you have a beginning gravity and an end gravity, it's pretty easy to figure an approximate ABV for your beverage.

The only way to definitively tell how much alcohol is in a solution is to run it through a Ebulliometer, which is essentially a tiny alcohol still. Sorry, that's the only real ways to do it!

2
  • As your link suggests then an Ebulliometer is not meant for hobby level brewing, it is very expensive. It there something like a hobby level version of this? I am thinking as long as I am within 0.5 ABV of the actual alcohol content it will be good enough for me
    – Jeppe
    Commented Feb 12, 2019 at 10:05
  • 1
    No. There is nothing. Those are your choices. You can send it to a lab for them to tell you how much alcohol and it's fairly cheap. Commented Feb 12, 2019 at 13:21

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.