4

I bought a hydrometer to level up a bit my game, It works great for Initial Gravity measures, it has a range from 0.997 to 1.100. My problem comes when it finishes the fermentation, I get a very VERY dry mead which the hydrometer ranges doesn't work, it gets almost completely submerged, I think my FG is around 0.990.

My question is, how can I measure it without diluting the mead. I can add honey as I usually aim to 1.005~1.010 finish gravity. But it's kind hard to estimate how much honey do I need to add in order to get in this range.

Any ideas?

2 Answers 2

4

Actually this shouldn't be too hard, provided you have an accurate scale. You can simply dissolve some white table sugar in your mead and compare the reading you get with the reading you would expect to get if you had dissolved the same amount of sugar in water instead. The difference will tell you how far below SG 1.000 (density of water) you are.

For example:

  • Say you took 5 grams of sugar (sucrose) and dissolved it in 95 grams of water. This would give you a 5% solution (5 grams of sugar out of the total weight of 100 grams). This is the same as 5 degrees Plato or SG 1.020 (for all intents and purposes, degrees Plato times four gives you the last two digits of SG [5 x 4 = 20, hence 1.020]).

  • If you used your mead instead of water you should measure a lower number. Say you added 5 grams of sugar to 95 grams of the mead, took a gravity reading, and got 1.008. Since you know using water should have given you 1.020, you can assume you started with liquid that was 0.012 SG lower than water (1.020 - 1.008), or 0.988.

It may be more trouble than it's worth, but it should let you know the gravity to a fair degree of accuracy. It would be best to do everything at room temperature, both for accuracy of hydrometer measurements and to avoid evaporating any liquid.

Edit: I should have noted that degrees Plato is the same as the percentage of sucrose in aqueous solution (i.e. 12.5 degrees Plato is the same as a 12.5% sucrose solution). Obviously mead/beer/cider/whatever have different sugars in solution, as well as alcohol and other soluble materials, but they are measured as the equivalent weight of sucrose.

Another edit: The formula to add enough sugar to a given amount of liquid to make a 5% (or any percentage) solution is as follows:

Ws = [ % * Wl ] \ [ 1 - %]

where:
  Ws = weight of sugar to add
  % = desired percentage of soultion (expressed as % / 100, so 5% would be 0.05)
  Wl = weight of liquid to which you will add the sugar

And working through a hypothetical example: you fill your hydrometer tube enough for a measurement and the weight of that liquid is 162 grams. You want to add sugar to make a 5% solution, which should get the hydrometer to read in range. So the weight of sugar you want to add is

= [ 0.05 * 162 g ] \ [ 1 - .05 ]
= 8.1 \ 0.95
= ~8.53 grams

And let's just check our math quickly: our resulting solution weighs 162 g + 8.5 g = 170.5 g.

8.5 / 170.5 = 0.0498

or basically 5%. Cool!

2
  • That seems like a great idea, I will try it later. How much solution do I need? I have a very accurate scale(1000/0.01g) Commented Feb 19, 2017 at 17:34
  • You need at least enough to fill your hydrometer tube. Why not take that, fill it enough for a measurement with your mead, then weigh that volume and add enough sugar to make a 5% solution. I will edit the necessary formula for that into my answer. 5% should be more than enough to get you above 1.000 (by adding 0.020 points) and is probably a good choice, but you could use any percentage as long as it gets you above the bottom of your hydrometer's scale. Commented Feb 19, 2017 at 17:57
0

There are other hydrometers available that cover a tight range at the low end. Regardless of the reading however, if you add more honey to raise the gravity it will just ferment out again. Unless you plan to stabilize the mead with sorbates or sulfites.

1
  • I add the honey before drinking. I was looking for a way to measure without resorting to buying a new hydrometer, but thanks anyway. Commented Feb 18, 2017 at 7:53

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.