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jsled
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Well, that's a nice problemYour high efficiency is due to have. :) You haveusing a couplelot more water than you need, washing every last bit of options:

1/ Collect less liquorsugar out of the mash. Ultimately, acceptyou want to collect less wort. This will result in a lower efficiency. 90% efficiency is neatAs such, but no one says youyou'll need to maximize your efficiency; you're not in a competition. Collectuse more grain to account for the pre-boil volume you needlower efficiency.

2/ Use less grainIf you had 22L at 17°Bx, then you started with 35L at 10°Bx with 90% efficiency. With this optionIf you instead want ~25L (assuming about a 10% evaporation for a 60 minute boil, you're going to target the sameymmv) at ~15°Bx, and assuming 75% efficiency, but you're goingyou might need to use less~30% more grain and thus less water.

X units grain * 90% extraction = 10°BX * 35L , and should end up at a happy medium where you're getting high-efficiency from lessX = 388

Y units grain and still hitting your target gravity and pre-boil volume* 75% extraction = 15°Bx * 25L, Y = 500

500/388 = ~1.29

Some mix of those twoBut your brewhouse is probably the right solutiongoing to have its own particulars, so brew, measure, math and repeat.

Well, that's a nice problem to have. :) You have a couple of options:

1/ Collect less liquor, accept a lower efficiency. 90% efficiency is neat, but no one says you need to maximize your efficiency; you're not in a competition. Collect to the pre-boil volume you need.

2/ Use less grain. With this option, you're going to target the same efficiency, but you're going to use less grain and thus less water, and should end up at a happy medium where you're getting high-efficiency from less grain and still hitting your target gravity and pre-boil volume.

Some mix of those two is probably the right solution.

Your high efficiency is due to using a lot more water than you need, washing every last bit of sugar out of the mash. Ultimately, you want to collect less wort. This will result in a lower efficiency. As such, you'll need to use more grain to account for the lower efficiency.

If you had 22L at 17°Bx, then you started with 35L at 10°Bx with 90% efficiency. If you instead want ~25L (assuming about a 10% evaporation for a 60 minute boil, ymmv) at ~15°Bx, and assuming 75% efficiency, you might need to use ~30% more grain.

X units grain * 90% extraction = 10°BX * 35L , X = 388

Y units grain * 75% extraction = 15°Bx * 25L, Y = 500

500/388 = ~1.29

But your brewhouse is going to have its own particulars, so brew, measure, math and repeat.

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jsled
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Well, that's a nice problem to have. :) You have a couple of options:

1/ Collect less liquor, accept a lower efficiency. 90% efficiency is neat, but no one says you need to maximize your efficiency; you're not in a competition. Collect to the pre-boil volume you need.

2/ Use less grain. With this option, you're going to target the same efficiency, but you're going to use less grain and thus less water, and should end up at a happy medium where you're getting high-efficiency from less grain and still hitting your target gravity and pre-boil volume.

Some mix of those two is probably the right solution.