Take the 2-minute tour ×
Homebrewing Stack Exchange is a question and answer site for dedicated home brewers and serious enthusiasts. It's 100% free, no registration required.

I have seen several tables, notably,

http://winemaking.jackkeller.net/hydrom.asp

http://www.beer-wine.com/learning/how-adjust-specific-gravity

http://www.brsquared.org/wine/CalcInfo/HydSugAl.htm

But they all differ slightly. I'd like to test my hydrometer and refractometer with known gravities by adding sugar to a known volume of water (say 1 gallon for example) and taking measurements (like with no sugar, then the correct amount for 1.010/2.5Brix, etc), then increase the sugar and continue taking measurements, just to verify the readings. However, I can't seem to find where they are getting the numbers from for oz/gallon of sugar. Notably, Jack's table includes sugar added to water, which I believe would be the most useful, since I'll measure the water first, then add the sugar.

share|improve this question
add comment

2 Answers

This post from adjelange has some more substantial detail, along with a "tl;dr:" that says basically: 1.046 for 1 lb in 1 gallon, and "The density does depend on the type of sugar but is not something you would be able to detect with a hydrometer."

(I found this by doing a google search for "sucrose gravity"; it was the first result.)

share|improve this answer
    
Heh, nice. I will read through that and see if I can glean the formula. –  Wyrmwood Sep 4 '13 at 15:45
add comment

OK, it appears the answer can be derived from the simple fact that "The [Plato] scale expresses the density as the percentage of sucrose by weight". By that token, the sugar content in oz is simply

8.3*16 * degrees plato or brix

To account for adding to water, you could say

(8.3*16)P%+(P%(8.3*16)*P%)

Obviously, the formula you use determine brix would play a large factor as well as the fact that the relationship between degrees Plato and specific gravity (SG) is not linear. I guess that's why Ball, Ack and Plato used tables...

share|improve this answer
add comment

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.